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"An error in ref. [1] "Local Causality in a FriedmannRobertsonWalker Spacetime"? How about equation (23) of http://arxiv.org/pdf/1405.2355v3.pdf . The set Lambda is empty."
Richard, are you deliberately trying to mislead? The followup is " ... this set is invariant under the rotations of n."
Invariance under rotation defines continuation into the codomain.
Don't you understand after all this time that Joy's framework is analytical and nonlinear  not dependent on detector choice of settings? You are still arguing with a strawman.
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06202016, 03:43 PM
(This post was last modified: 06212016, 06:51 AM by Schmelzer.)
I hadn't forgotten, but was ignoring, the part at the end, trying to give maximum benefit of the doubt. As I said I'm supposing that nonsense onepager is the result of insanity or something, and was tacked on to this paper while in that state. It occurrred to me to mention that, but didn't realize how nitpicky you'd be.
As for eqn 23, let's see. nu sub ze0, ... Don't remember what z was and don't feel like hunting for it, but this is some angle, conceivably pi or greater AFAIK. kappa is +1 (could be 1, ignore that), the 2 / sqrt term could therefore actually equal precisely 1 , so 1 plus it could be = 0, in which case abs val of cos would always be >= it, and the set nonempty. Perhaps if I cared what z was I'd see that sometimes the condition becomes nontrivial, and for some n (it does say "for all n") it fails. So I can believe that it's always empty as you say. But it's not immediately obvious, and I still don't know  or care. Since I was overallreviewing this thing, looking for gross errors, I let that slide and never came back to it.
I spent a couple hours (2 1/2), had to remember Clifford algebra, review FLRW, go through this and his two other papers (dozen pages of completely unfamiliar stuff). Found gross errors, and was done. To make it an unbiased trial ignored your and Schmelzer's criticisms for the exercise.
It's interesting to note the "s goes to a and b simultaneously" error can be analyzed two different ways; your way and the one I came up with. I supposed he meant to have two s's with subscripts going to a and b separately, (giving max benefit of doubt) but still get 1 correlation (obviously). Whereas you suppose it forces a to equal b, giving same result. You're not giving benefit of doubt; your supposition would be very dumb. Still, it's pretty dumb my way also.
Anyway I felt rather proud of myself. Now you come back to tell me (after I agree with you!) that I should have seen an error in (23). Note, you've studied this thing for 2 1/2 years, not hours. Instead of thanking me for the effort, you point this out and also mention about the end of the paper reproducing the onepager, as though I didn't notice it. Gratuitously mentioning, after I said I couldn't see anything wrong, after studying Clifford algebra and other background material for two hours and then spending 20 minutes on it, that it's "incoherent from beginning to end". Thanks for the vote of confidence.
I'm beginning to understand how it is that this circus has lasted so long. [...]
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Secur wrote: "It's interesting to note the 's goes to a and b simultaneously' error can be analyzed two different ways; your way and the one I came up with. I supposed he meant to have two s's with subscripts going to a and b separately, (giving max benefit of doubt) but still get 1 correlation (obviously). Whereas you suppose it forces a to equal b, giving same result."
Then there's the third (and correct) way: by analytic continuation through a point at infinity to the codomain S^3. Due to special relativity, the speed of light limit makes the measure finite and local.
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06202016, 05:37 PM
(This post was last modified: 06202016, 05:45 PM by FrediFizzx.)
(06202016, 09:28 AM)secur Wrote: The paper linked to above by gill1109, "Disproof of Bell’s Theorem" contains elementary errors, as he says. You can blame it on taking the limit of s as it goes to both a and b; Schmelzer gave another way to look at it a while ago, I believe. The correlation is 1, not (a.b).
Joy Christian should not have published those onepagers, they're too easy to figure out; even I can do it. ref. [1], is much harder and I still don't know where the error is. Unfortunately I started with that one; should have started with the onepagers. Sorry but you still don't understand the one page paper. If you get the result of 1 then you are rejecting the \(S^3\) postulate.
There are two particles which both have "s" from their common creation. One particle's "s" goes to "a" the other goes to "b". It is quite simple really. Don't let Gill confuse you about that.
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06212016, 04:18 AM
(This post was last modified: 06212016, 07:00 AM by FrediFizzx.)
(06202016, 03:43 PM)secur Wrote: As for eqn 23, let's see. nu sub ze0, ... Don't remember what z was and don't feel like hunting for it, but this is some angle, conceivably pi or greater AFAIK. kappa is +1 (could be 1, ignore that), the 2 / sqrt term could therefore actually equal precisely 1 , so 1 plus it could be = 0, in which case abs val of cos would always be >= it, and the set nonempty. Perhaps if I cared what z was I'd see that sometimes the condition becomes nontrivial, and for some n (it does say "for all n") it fails. So I can believe that it's always empty as you say. 
You had it mostly right at first. It is definitely nonempty. Gill is again trying his best to mislead. It is just a condition for determining what the complete states are. Very important because you can't detect what isn't there in the first place.
Trust me, I am not going to mislead you.
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06212016, 06:36 AM
(This post was last modified: 06212016, 07:00 AM by Schmelzer.)
(06202016, 05:37 PM)FrediFizzx Wrote: There are two particles which both have "s" from their common creation. One particle's "s" goes to "a" the other goes to "b". It is quite simple really. Is this the way one has to interpret the formula containing some meaningless limit operation of the type \[\lim_{s\to a\,\,s\to b} F(s)?\]
In this case, the reasonable way would be to distinguish the two versions of s and write a formula distinguishing them, like
\[\lim_{s_1\to a\,\,s_2\to b} F(s_1, s_2).\]
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06212016, 06:42 AM
(This post was last modified: 06212016, 07:30 AM by FrediFizzx.)
(06212016, 04:18 AM)FrediFizzx Wrote: (06202016, 03:43 PM)secur Wrote: As for eqn 23, let's see. nu sub ze0, ... Don't remember what z was and don't feel like hunting for it, but this is some angle, conceivably pi or greater AFAIK. kappa is +1 (could be 1, ignore that), the 2 / sqrt term could therefore actually equal precisely 1 , so 1 plus it could be = 0, in which case abs val of cos would always be >= it, and the set nonempty. Perhaps if I cared what z was I'd see that sometimes the condition becomes nontrivial, and for some n (it does say "for all n") it fails. So I can believe that it's always empty as you say. 
You had it mostly right at first. It is definitely nonempty. Gill is again trying his best to mislead. It is just a condition for determining what the complete states are. Very important because you can't detect what isn't there in the first place.
Trust me, I am not going to mislead you. _
Well, you are probably going to ask why you should trust me. First of all I am not going to tell you lies. I have been studying Joy Christian's work for a very long time and know it pretty well and I would rather spend my time teaching you the truth about it if you really want to know it better. It seems like you do. Perhaps it intrigues you a bit.
It really just boils down to this. If you accept the postulates of the model, then Bell was wrong. If you don't accept the postulates of the model, then I probably can't teach you anything about it. Here are the very simple physically sensible postulates again.
1. In the EPRBohm scenario, the particle pairs as a system can be either left or right hand oriented (hidden variable).
2. And they behave via parallelized 3sphere topology.
That is all there is to it for the postulates.
(06212016, 06:36 AM)Schmelzer Wrote: (06202016, 05:37 PM)FrediFizzx Wrote: There are two particles which both have "s" from their common creation. One particle's "s" goes to "a" the other goes to "b". It is quite simple really. Is this the way one has to interpret the meanigless formula containing \[\lim_{s\to a\,\,s\to b}?\] _
How else would someone interpret it? This is about the EPRBohm scenario after all. If helps you to keep track of it, you could label them as \(s_A\) and \(s_B\) with \(s = s_A = s_B\).
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06212016, 07:04 AM
(This post was last modified: 06212016, 07:11 AM by Schmelzer.)
[Sorry for having edited my post during the time you were answering. So, what FrediFizzx has quoted was, at that moment, my complete answer.]
(06212016, 06:42 AM)FrediFizzx Wrote: How else would someone interpret it? This is about the EPRBohm scenario after all. If helps you to keep track of it, you could label them as \(s_A\) and \(s_B\) with \(s = s_A = s_B\). Sorry, formulas should not have any freedom for interpretation. Anyway, a formula of type
\[ \lim_{s_A\to a\,\, s_B\to b} F(s_A, s_B)\]
does not make sense if, on the one hand, \(s = s_A = s_B\), and, on the other hand, \(a\neq b\).
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06212016, 07:08 AM
(This post was last modified: 06212016, 07:46 AM by gill1109.)
(06202016, 03:43 PM)secur Wrote: I hadn't forgotten, but was ignoring, the part at the end, trying to give maximum benefit of the doubt. As I said I'm supposing that nonsense onepager is the result of insanity or something, and was tacked on to this paper while in that state. It occurred to me to mention that, but didn't realize how nitpicky you'd be.
I'm sorry to hurt your feelings! It was not deliberate. In fact I was very happy to find someone else who could see through the onepage paper.
Regarding the set Lambda in equation (23) of http://arxiv.org/pdf/1405.2355v3.pdf which is empty: I certainly did not mean to imply that this was obvious. You have to go back and check the definitions of everything. You made the very perspicacious remark that it does say "for all n". That's where it goes wrong. The condition is not trivial and it is not invariant to choice of n, in contradiction to what is stated between equations (20) and (23). As you vary n arbitrarily you eventually exclude everything.
I'm afraid that it does require some nitpicking in order to expose the incoherence.
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(06212016, 07:04 AM)Schmelzer Wrote: [Sorry for having edited my post during the time you were answering. So, what FrediFizzx has quoted was, at that moment, my complete answer.]
(06212016, 06:42 AM)FrediFizzx Wrote: How else would someone interpret it? This is about the EPRBohm scenario after all. If helps you to keep track of it, you could label them as \(s_A\) and \(s_B\) with \(s = s_A = s_B\). Sorry, formulas should not have any freedom for interpretation. Anyway, a formula of type
\[ \lim_{s_A\to a\,\, s_B\to b} F(s_A, s_B)\]
does not make sense if, on the one hand, \(s = s_A = s_B\), and, on the other hand, \(a\neq b\).
I certainly hope you realize that is not true in the case of the EPRBohm scenario. Remember; two different particles with the same "s". At the A detection station the A particle's "s" goes to a. At the B station the B particle's "s" goes to b. I am not sure at all why you are having trouble with that. ???
